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// the keys that are currently pressed Keys[] pressedKeys; pressedKeys = keyState.GetPressedKeys(); // work through each key that is presently pressed for (int i = 0; i < pressedKeys.Length; i++) { // set a flag to indicate we have not found the key bool foundIt = false; // work through each key that was previously pressed for (int j = 0; j < oldKeys.Length; j++) { if (pressedKeys[i] == oldKeys[j]) { // we found the key in the previously pressed keys foundIt = true; } } if (foundIt == false) { // if we get here we didn't find the key in the old keys, so // add the key to the end of the message string messageString = messageString + pressedKeys[i].ToString(); } } // remember the currently pressed keys for next time oldKeys = pressedKeys; base.Update(gameTime); }

You can also instantiate new Cursor objects for example, by loading a cursor from a .cur file. (The Cursor class doesn t support animated cursors in .ani files.) You just have to pass the name of the file to the class constructor, as in this line of code:

Dim cur As New Cursor( c:\Windows\cursors\3dsmove.cur )

You also can use an overloaded variation of the constructor to load the cursor from a stream, which is useful if a file contains multiple cursors. After you create a cursor, you can assign it to the Cursor.Current property or to the Cur sor property of a control. It s important, however, that you destroy the cursor in an orderly fashion when you don t use it any longer for example, when you restore the default cursor shape for the control:

Dim cur As New Cursor( c:\Windows\cursors\3dsmove.cur )

This class replaces the command of the same name that you use under Visual Basic 6. With its Send shared method, you can send one or more keystrokes to the active appli cation for example:

This version of Update takes each key in the pressedKeys array and searches the oldKeys array to see if that key is in there. If it doesn t find the key, it adds a description of the key to the message string. I ve added quite a few comments (the lines that start with //) that should make the code easier to understand. Note that I am using a bool variable called foundIt to record whether a key has been found when the old key array is searched. If this flag is not set during a search, that key value is not present in the old array and must be a new key. The message string itself is drawn in the same way as it was in the previous program. Don t worry if you find this code confusing at first; just remember the problem that it is trying to solve. The program has two lists of keys, an old list and a new list. It is trying to detect new arrivals (that is, those who are in the new list but not in the old one). You would use the same algorithm if you were in charge of greeting people arriving at a party. Every now and then, you would look around and try to spot any new faces that you hadn t seen before. If you were organized, you would keep a list of those people you have seen, and then look out for people not on that list. If you look at the code, you should find that it is doing exactly that.

A text box containing the selected text appears in the message. Move the text box to the right side of the page, under the horizontal line. Tip You can turn on boundaries and guides to view the text box outlines in the e-mail message.

SendKeys.Send( VB~ )

(If sent to a text field, this sequence deletes the current line.)

SendKeys.Send( {HOME}+{END}{DEL} )

SendKeys.SendWait( {* 40}{LEFT 40} )

Sample Code: First Message Display The MessageBoard project n the 02 F rst Message D sp ay d rectory n the resources for th s chapter conta ns a program that uses the Update method from th s sect on to bu d and d sp ay a message from the keys that are pressed on the keyboard If you look closely at the code in Update, you find that at the end of the method, the value of oldKeys is set to refer to the pressedKeys array so that the next time that Update is called, it will have some old keys to check against. However, the very first time that Update is called, there are no old keys. This problem has been solved by making oldKeys refer to an empty array when the variable is declared: